python获取本周周一或周末日期_是泛小舟啊？的博客

today = datetime.strptime(str(today), "%Y%m%d") return datetime.strftime(today - timedelta(today.weekday()), "%Y%m%d")

2. 获取本周周日日期

from datetime import datetime, timedelta
def this_sunday(today):
    :function: 获取本周周日日期
    :param today:
    :return: 返回周日日期
    :return_type: string
    today = datetime.strptime(str(today), "%Y%m%d")
    return datetime.strftime(today + timedelta(7 - today.weekday() - 1), "%Y%m%d")

1. 获取本周周一日期用timedelta函数做一个小算法：from datetime import datetime, timedeltadef this_monday(today): """ :function: 获取本周周一日期 :param today: :return: 返回周一的日期 :return_type: string """ today = datetime.strptime(str(today), "%Y%m%d"

Python 日期和时间 Python 程序能用很多方式处理日期和时间，转换日期格式是一个常见的功能。 Python 提供了一个 time 和 calendar 模块可以用于格式化日期和时间。时间间隔是以秒为单位的浮点小数。每个时间戳都以自从1970年1月1日午夜（历元）经过了多长时间来表示。 Python 的 time 模块下有很多函数可以转换常见日期格式。如函数time.time()用于获取当前时间戳, 如下实例: #!/usr/bin/ python # -- coding: UTF-8 --

def get_current_week(): monday, sunday = datetime.date.today(), datetime.date.today() one_day = datetime.timedelta(days=1) while monday.weekday() != 0: monday -= one_day while sunday.weekday() != 6: sunday +

def get_current_week(): monday, sunday = datetime.date.today(), datetime.date.today() one_day = datetime.timedelta(days=1) while monday.weekday() != 0: monday -= one_day while sunday.weekday() != 6: sunday += one_day print "Month: %d" % now.month print "Day: %d" % now.day print "Weekday: %d" % now.weekday() # Day of week Monday = 0, Sunday = 6 print "Ho

static void printTriangle(int row){ int[][] array=new int[row][]; for (int i = 0; i < array.length; i++) { array[i]=new int[i+1]; for (int j = 0; j < array[i].length; j++) { if (i<=1||j==0||j==i) { array[i][j]=1; System.out.print(array[i][j]+" "); continue; array[i][j]=array[i-1][j]+array[i-1][j-1]; System.out.print(array[i][j]+" "); System.out.println(); //杨辉三角 python获取本周周一或周末日期山茶花开时。: 嗯嗯，之后自己解决了，谢谢博主 python获取本周周一或周末日期是泛小舟啊？: today参数你要在调用函数时传进来的，格式为"%Y%m%d"，比如：20220607，也可以通过时间函数直接获取今日日期 python获取本周周一或周末日期山茶花开时。: today参数运行不成功