Runs CherryPy WSGI server hosting WSGI app func. The directory static/ is hosted statically.

Example code

import web
class MyApplication(web.application):
    def run(self, port=8080, *middleware):
        func = self.wsgifunc(*middleware)
        return web.httpserver.runsimple(func, ('0.0.0.0', port))
if __name__ == "__main__":
    app = MyApplication(urls, globals())
    app.run(port=8888)
If you're using web.py's built-in webserver, you can just append the port to the command:
python app.py 8080
I haven't tried ever with the listening address, but perhaps it will accept 1.2.3.4:8080 as the format.
                Good intuition, it accepts address too. Although, I would like to use my own command line parsing and do not mix it with default web.py command line parser
– Jakub M.
                Jan 21, 2013 at 18:32
                Do you mean to run it from a 'normal' webserver like Apache or something? If that's the case, you'll need to play around with the Apache config to determine which address/port combo should point to your script.
– Dan
                Jan 21, 2013 at 18:35
server_addr = validip(listget(sys.argv, 1, ''))
if os.environ.has_key('PORT'): # e.g. Heroku
    server_addr = ('0.0.0.0', intget(os.environ['PORT']))
return httpserver.runsimple(func, server_addr)
so, you can set the web server port by add environ variable:
import os
os.environ["PORT"] = "80"
        
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