在不分割字符的情况下将字符串转换为元组

   a = 'Quattro TT'
   print tuple(a)

  a = ['Quattro TT']  
  print tuple(a)

a = 'Quattro TT'
print tuple(list(a))

('Quattro TT')

('Q', 'u', 'a', 't', 't', 'r', 'o', ' ', 'T', 'T')

class Sequence( tuple ):
    def __init__( self, *args ):
        # initialisation...
        self.instances = []
    def __new__( cls, *args ):
        for arg in args:
            assert isinstance( arg, unicode ), '# arg %s not unicode' % ( arg, )
        if len( args ) == 1:
            seq = super( Sequence, cls ).__new__( cls, ( args[ 0 ], ) )
        else:
            seq = super( Sequence, cls ).__new__( cls, args )
        print( '# END new Sequence len %d' % ( len( seq ), ))
        return seq

Sequence( u'silly' )

Sequence( u'silly', )

import ast
def parse_tuple(string):
        s = ast.literal_eval(str(string))
        if type(s) == tuple:
            return s
        return
    except:
        return

parse_tuple('("A","B","C",)')  # Result: ('A', 'B', 'C')

value = parse_tuple("('%s',)" % a)

a = ‘Quattro TT’
print tuple(a)

list_users = (‘test1’, ‘test2’, ‘test3’)
and the i get from file
tmp = config_ob.get(section_name, option_name)
>>>”(‘test1’, ‘test2’, ‘test3’)”

def fot_tuple(self, some_str):
     # (‘test1’, ‘test2’, ‘test3’)
     some_str = some_str.replace(‘(‘, ”)
     # ‘test1’, ‘test2’, ‘test3’)
     some_str = some_str.replace(‘)’, ”)
     # ‘test1’, ‘test2’, ‘test3’
     some_str = some_str.replace(“‘, ‘”, ‘,’)
     # ‘test1,test2,test3’
     some_str = some_str.replace(“‘”, ‘,’)
     # test1,test2,test3
     # and now i could convert to tuple
     return tuple(item for item in some_str.split(‘,’) if item.strip())

s="jack"
tup=tuple(s.split(" "))
output=('jack')

'Quattro TT'

['Q', 'u', 'a', 't', 't', 'r', 'o', ' ', 'T', 'T']

['Quattro TT']

a = 'Quattro TT'
list(a)

tuple(something)

>>> a = ['Quattro TT']  
>>> eval(str(a))
['Quattro TT']

val_1=input("").strip(")(").split(",") #making a list from the string
if val_1[0].isdigit()==True: #checks if your contents are all integers
  val_2 = []
  for i in val_1:
    val_2.append(int(i))
  val_2 = tuple(val_2)
  print(val_2)
else: # if the contents in your tuple are of string, tis case is applied
  val_2=[]
  for i in range(0,len(val_1)):
      if i==0:

在不分割字符的情况下将字符串转换为元组

9 个回答