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It's not exactly clear how you want to search the array. Here are some alternatives:
Find all items containing the exact string "Ra" (returns items 2 and 3):
Dim result As String() = Array.FindAll(arr, Function(s) s.Contains("Ra"))
Find all items starting with the exact string "Ra" (returns items 2 and 3):
Dim result As String() = Array.FindAll(arr, Function(s) s.StartsWith("Ra"))
Find all items containing any case version of "ra" (returns items 0, 2 and 3):
Dim result As String() = Array.FindAll(arr, Function(s) s.ToLower().Contains("ra"))
Find all items starting with any case version of "ra" (retuns items 0, 2 and 3):
Dim result As String() = Array.FindAll(arr, Function(s) s.ToLower().StartsWith("ra"))
If you are not using VB 9+ then you don't have anonymous functions, so you have to create a named function.
Example:
Function ContainsRa(s As String) As Boolean
Return s.Contains("Ra")
End Function
Usage:
Dim result As String() = Array.FindAll(arr, ContainsRa)
Having a function that only can compare to a specific string isn't always very useful, so to be able to specify a string to compare to you would have to put it in a class to have somewhere to store the string:
Public Class ArrayComparer
Private _compareTo As String
Public Sub New(compareTo As String)
_compareTo = compareTo
End Sub
Function Contains(s As String) As Boolean
Return s.Contains(_compareTo)
End Function
Function StartsWith(s As String) As Boolean
Return s.StartsWith(_compareTo)
End Function
End Class
Usage:
Dim result As String() = Array.FindAll(arr, New ArrayComparer("Ra").Contains)
Sub Main()
Dim arr() As String = {"ravi", "Kumar", "Ravi", "Ramesh"}
Dim result As New List(Of Integer)
For i As Integer = 0 To arr.Length
If arr(i).Contains("ra") Then result.Add(i)
End Sub
End Module
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string[] strArray = { "ABC", "BCD", "CDE", "DEF", "EFG", "FGH", "GHI" };
Array.IndexOf(strArray, "C"); // not found, returns -1
Array.IndexOf(strArray, "CDE"); // found, returns index
compare properties in the array if one matches the input then set something to the value of the loops current position, which is also the index of the current looked up item.
simple eg.
dim x,y,z as integer
dim aNames, aIndexes as array
dim sFind as string
for x = 1 to length(aNames)
if aNames(x) = sFind then y = x
y is then the index of the item in the array, then loop could be used to store these in an array also so instead of the above you would have:
z = 1
for x = 1 to length(aNames)
if aNames(x) = sFind then
aIndexes(z) = x
z = z + 1
endif
Dim arr() As String = {"ravi", "Kumar", "Ravi", "Ramesh"}
Dim result = arr.Where(Function(a) a.Contains("ra")).Select(Function(s) Array.IndexOf(arr, s)).ToArray()
string[] arr = { "ravi", "Kumar", "Ravi", "Ramesh" };
var result = arr.Where(a => a.Contains("Ra")).Select(a => Array.IndexOf(arr, a)).ToArray();
-----Detailed------
Module Module1
Sub Main()
Dim arr() As String = {"ravi", "Kumar", "Ravi", "Ramesh"}
Dim searchStr = "ra"
'Not case sensitive - checks if item starts with searchStr
Dim result1 = arr.Where(Function(a) a.ToLower.StartsWith(searchStr)).Select(Function(s) Array.IndexOf(arr, s)).ToArray
'Case sensitive - checks if item starts with searchStr
Dim result2 = arr.Where(Function(a) a.StartsWith(searchStr)).Select(Function(s) Array.IndexOf(arr, s)).ToArray
'Not case sensitive - checks if item contains searchStr
Dim result3 = arr.Where(Function(a) a.ToLower.Contains(searchStr)).Select(Function(s) Array.IndexOf(arr, s)).ToArray
End Sub
End Module
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Never use .ToLower and .ToUpper.
I just had problems in Turkey where there are 4 "i" letters. When using ToUpper I got the wrong "Ì" one and it fails.
Use invariant string comparisons:
Const LNK as String = "LINK"
Dim myString = "Link"
If myString.ToUpper = LNK Then...
Good and works in the entire world:
If String.Equals(myString, LNK , StringComparison.InvariantCultureIgnoreCase) Then...
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